|
|
100黑幣
請教大神。實(shí)現(xiàn)利用按鍵K1控制數(shù)碼管DS6顯示9~0的倒計(jì)時(shí),按鍵每按下一次,數(shù)字減一。只顯示0,請大神幫我指指錯(cuò)誤,下面是我的代碼:
#include <reg52.h>
sbit ADDR0 = P1^0;
sbit ADDR1 = P1^1;
sbit ADDR2 = P1^2;
sbit ADDR3 = P1^3;
sbit ENLED = P1^4;
sbit K1 = P2^4;
unsigned char code LedChar[] = {
0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8,
0x80, 0x90, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E
};
void delay();
void main()
{
bit keybuf = 1; //按鍵值暫存,臨時(shí)保存按鍵的掃描值
bit backup = 1; //按鍵值備份,保存前一次的掃描值
unsigned char cnt = 0; //按鍵計(jì)數(shù),記錄按鍵按下的次數(shù)
unsigned int j;
ENLED = 0; //選擇數(shù)碼管 DS6進(jìn)行顯示
ADDR3 = 1;
ADDR2 = 1;
ADDR1 = 0;
ADDR0 = 1;
P2 = 0xF7; //P2.3 置 0,即 KeyOut1 輸出低電平
P0 = LedChar[j]; //顯示值
while (1)
{
keybuf = j; //把當(dāng)前掃描值暫存
if (keybuf != backup) //當(dāng)前值與前次值不相等說明此時(shí)按鍵有動(dòng)作
{
delay(); //延時(shí)大約 10ms
if (keybuf == j) //判斷掃描值有沒有發(fā)生改變,即按鍵抖動(dòng)
{
if (backup == 0) //如果前次值為 0,則說明當(dāng)前是彈起動(dòng)作
{
cnt++; //按鍵次數(shù)+1
j--;
if (cnt >= 9)
{ //只用 1 個(gè)數(shù)碼管顯示,所以加到 10 就清零重新開始
cnt = 0;
j = 9;
}
P0 = LedChar[j]; //計(jì)數(shù)值顯示到數(shù)碼管上
}
backup = keybuf; //更新備份為當(dāng)前值,以備進(jìn)行下次比較
}
}
} }
/* 軟件延時(shí)函數(shù),延時(shí)約 10ms */
void delay()
{
unsigned int i = 1000;
while (i--);
}
|
-
|