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標題: 請問下我16*16點陣顯示一個漢字的程序有問題嗎？ [打印本頁]

作者: 成都勒布朗 時間: 2020-6-26 14:05
標題: 請問下我16*16點陣顯示一個漢字的程序有問題嗎？
1個74154驅動陰極，2個74595驅動陽級，為什么我仿真出來的“二”這個字的上下兩橫反復跳？速度一會快一會兒慢程序如下：
#include <reg52.h>
//#include <intrins.h>
#define uint unsigned int
#define uchar unsigned char
sbit DS=P2^4;
sbit SH=P2^5;
sbit ST=P2^6;
sbit A_port=P1^0;
sbit B_port=P1^1;
sbit C_port=P1^2;
sbit D_port=P1^3;
/*
0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,
0xF8,0x0F,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,
0xFF,0xFF,0xFF,0xFF,0xC0,0x01,0xFF,0xFF,
0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF,0xFF
*///二
uchar dian_H[]={
0xFF,0xFF,0xFF,0xFF,
0xF8,0xFF,0xFF,0xFF,
0xFF,0xFF,0xC0,0xFF,
0xFF,0xFF,0xFF,0xFF
};//列碼高8位
uchar dian_L[]={
0xFF,0xFF,0xFF,0xFF,
0x0F,0xFF,0xFF,0xFF,
0xFF,0xFF,0x01,0xFF,
0xFF,0xFF,0xFF,0xFF
};//列碼低8位

/*列選函數*/
void Sendbyte(uint dat1,uint dat2)//dat1為列碼低八位，dat2為高八位
{
uchar i;
ST=0;
for(i=0;i<8;i++)//將列碼低八位發送至595的移位寄存器
{
SH=0;
if(dat1&0x01)
DS=1;
else
DS=0;//取列碼的最低位，若為1則DS輸入1，若為0則DS輸入0
SH=1;
dat1=dat1>>1;
}
for(i=0;i<8;i++)//將列碼高八位發送至595的移位寄存器
{
SH=0;
if(dat2&0x01)
DS=1;
else
DS=0;
SH=1;
dat2=dat2>>1;
}
ST=1;
}
/*行選函數*/
void HX(uchar hang)
{
switch (hang)
{
  case 0:
D_port = 0; C_port = 0; B_port = 0; A_port = 0;//選第1行
break;
  case 1:
D_port = 0; C_port = 0; B_port = 0; A_port = 1;//選第2行
break;
  case 2:
D_port = 0; C_port = 0; B_port = 1; A_port = 0;//選第3行
break;
  case 3:
D_port = 0; C_port = 0; B_port = 1; A_port = 1;//選第4行
break;
  case 4:
D_port = 0; C_port = 1; B_port = 0; A_port = 0;//選第5行
break;
  case 5:
D_port = 0; C_port = 1; B_port = 0; A_port = 1;//選第6行
break;
  case 6:
D_port = 0; C_port = 1; B_port = 1; A_port = 0;//選第7行
break;
  case 7:
D_port = 0; C_port = 1; B_port = 1; A_port = 1;//選第8行
break;
  case 8:
D_port = 1; C_port = 0; B_port = 0; A_port = 0;//選第9行
break;
  case 9:
D_port = 1; C_port = 0; B_port = 0; A_port = 1;//選第10行
break;
  case 10:
D_port = 1; C_port = 0; B_port = 1; A_port = 0;//選第11行
break;
  case 11:
D_port = 1; C_port = 0; B_port = 1; A_port = 1;//選第12行
break;
  case 12:
D_port = 1; C_port = 1; B_port = 0; A_port = 0;//選第13行
break;
  case 13:
D_port = 1; C_port = 1; B_port = 0; A_port = 1;//選第14行
break;
  case 14:
D_port = 1; C_port = 1; B_port = 1; A_port = 0;//選第15行
break;
  case 15:
D_port = 1; C_port = 1; B_port = 1; A_port = 1;//選第16行
break;
  }
}
/*主函數*/
void main()
{
  uchar j;
while(1)
{
for(j=0;j<16;j++)
{
Sendbyte(dian_L[j],dian_H[j]);
HX(j);
   }
}
}

作者: 成都勒布朗 時間: 2020-6-26 14:33
是不是頻率的問題啊嗎，怎么通過編程設置他動態掃描的頻率啊

歡迎光臨 (http://m.raoushi.com/bbs/)