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標(biāo)題: 單片機(jī)紅外防盜加時(shí)鐘,兩個(gè)程序的整合問(wèn)題 [打印本頁(yè)]

作者: xiashunxuan233 時(shí)間: 2020-4-12 14:00
標(biāo)題: 單片機(jī)紅外防盜加時(shí)鐘,兩個(gè)程序的整合問(wèn)題
本人新手，C語(yǔ)言基礎(chǔ)較差，最近設(shè)計(jì)一個(gè)紅外防盜系統(tǒng)，要求加時(shí)鐘顯示時(shí)間和報(bào)警時(shí)段，然后自己通過(guò)仿真分別實(shí)現(xiàn)了紅外防盜和時(shí)鐘顯示（報(bào)警時(shí)段還有紕漏），但是整合成一個(gè)的時(shí)候1602顯示屏無(wú)法顯示，因?yàn)樗捷^差，自己一個(gè)人難有進(jìn)展，下面貼程序和仿真情況，請(qǐng)教各位大佬，希望能得到指導(dǎo)。
下面是兩個(gè)程序的整合，希望大佬稍微指導(dǎo)一下

#include<reg52.h>
#define uchar unsigned char
#define uint unsigned int
sbit huang=P2^0;//??
sbit lv=P2^2;//??
sbit hong=P2^4;//??

sbit hongwai=P1^0;//???
sbit butter=P2^6;//??????????

sbit baojing=P1^2;//??????;
sbit bufang=P1^3;//????
sbit quxiao=P1^4;//????
sbit lcdrs=P1^5;
sbit lcden=P1^6;
uchar tt=0;//?????
uchar num=0;//???????
uchar flag=0;//???
uchar count,s1num,s4num;
char miao,shi,fen;

void timer1init(void)//???1,16???2
{       EA=0;
  TMOD=0x11;//?????0?????1
      TH0=(65536-10000)/256;
      TL0=(65536-10000)%256;
      ET0=1;//????0??
      TR0=1;//?????0
      tt=0;//
      EA=0;//????
}
void delay(uint z)//????
{
      uint x,y;
      for(x=z;x>0;x--)
            for(y=110;y>0;y--);
}
void main()//???
{
   huang=0;//?????
               lv=0;//?????
               hong=0;//?????
               timer1init();//??????
               while(1)
               {

         if(!baojing)//??????????
                              {
                                    delay(5);//????
                                    if(!baojing)//???????????
                                    {
         hong=1;//???
                                       lv=0;       //???
                                       flag=7;//?????7
                                       butter=0;//????
                                       EA=0;//???
                                    }
                                    while(!baojing);//?????????
                                    delay(5);//????????
                                    while(!baojing);//???????
                              }
         if((!bufang)&&(flag<4))//????????????????????
                              {
                                    delay(5);//????
                                    if(!bufang)//???????
                                    {
                                       EA=1; //????
                                       flag=2;//?=2
                                    }
                                    while(!bufang);//????????
                                    delay(5);//??
                                    while(!bufang);//?????
                              }
                     if(!quxiao)//???????
                              {
                                    delay(5);//????
                                    if(!quxiao)//????????
                                    {
                                       flag=3;//FLAG??3
                                       butter=1;//?????
                                       tt=0;//
                                       num=0;//????0
                                       EA=0;//???
                                       lv=0;//???
                                       hong=0;//???
                                    }
                                    while(!quxiao);//??????
                                    delay(5);//????
                                    while(!quxiao);//??????

                              }
                  if(flag==4)//???????
                        {
                        tt=0;//????0
                        EA=0;//???
                        num=0;//??????
                        lv=1;//???
                        flag=5;//flag??5

                        }
                     if(hongwai)//?????????
                        huang=1;
                     else  huang=0;//????????

                     if(flag==5)//??flag??5
                        {
                           if(hongwai)//??????
                                 {
                                 butter=0;//????
                                 EA=1;//???
                                 }
                        }

               }
}

void write_com(uchar com)//???????
{
   lcdrs=0;
   lcden=0;
   P0=com;
   delay(5);
   lcden=1;
   delay(5);
   lcden=0;
}
void write_date(uchar date)//???????
{
   lcdrs=1;
   lcden=0;
   P0=date;
   delay(5);
   lcden=1;
   delay(5);
   lcden=0;
}
void write_alarm(uchar add1,uchar date1)//??????
{
   uchar shi,ge;
   shi=date1/10;//????2????????
   ge=date1%10;
   write_com(0x80+add1);//??????
   write_date(0x30+shi);//????????
   write_date(0x30+ge);//????????
}
void write_sfm(uchar add,uchar date)//??????
{
   uchar shi,ge;
   shi=date/10;//????2????????
   ge=date%10;
   write_com(0x80+0x40+add);//??????
   write_date(0x30+shi);//????????
   write_date(0x30+ge);//????????
}

void init()//?????
{
   lcden=0;
   shi=21;
   fen=59;
   miao=58;
   count=0;
   s1num=0;
   s4num=0;
   write_com(0x38);//???1602??
   write_com(0x0c);
   write_com(0x06);
   write_com(0x01);
   write_com(0x80);//????????


   delay(5);
   write_com(0x80+0x40+6);//???????????":"
   write_date(':');
   delay(5);
   write_com(0x80+0x40+9);
   write_date(':');
   delay(5);


                     write_sfm(10,miao);//????????
   write_sfm(7,fen);
   write_sfm(4,shi);

                     TMOD=0x01;//?????0????
   TH0=(65536-50000)/256;//??????
   TL0=(65536-50000)%256;
   EA=1;    //????
   ET0=1; //????0??
   TR0=1; //?????0
}

void printer()//???
{
   init();//????????
   while(1)//????????
                     {
                              if(hongwai==1)
                              {
                                                delay(5);
                              write_com(0x80+3);
            write_date('*');
                                          delay(5);
            write_com(0x80+6);
            write_date(':');
                                          delay(5);
            write_com(0x80+9);
            write_date(':');
                                          delay(5);
                              write_com(0x80+12);
            write_date('*');
            delay(5);

                                    write_alarm(4,shi);//????????
            write_alarm(7,fen);
            write_alarm(10,miao);

                              }
                     }
}

void timer0() interrupt 1
{
      TH0=(65536-50000)/256;
      TL0=(65536-50000)%256;
      tt++;
      if(tt==10)
      {tt=0; num++;}
      if((flag==5)&&(num%2==0))//??15????flag=5 ,num?????
         hong=1;
      if((flag==5)&&(num%2==1))//??15????flag=5 ,num?????
         hong=0;
      if((flag==2)&&(num%2==0))//??????flag??2,num?????
            lv=1;
      if((flag==2)&&(num%2==1)) // ??????flag??2,num?????
            lv=0;
      if((flag==2)&&(num==30))//????,num=30?15?,?????????????
         flag=4;
}

void timer1() interrupt 3
{

  TH1=(65536-50000)/256;
      TL1=(65536-50000)%256;
      count++;       //??????
   if(count==20)//20?50???1?
   {
            count=0;
            miao++;
            if(miao==60)//???60?????
            {
                  miao=0;//??????
                  fen++;
                  if(fen==60)//????60?????
                  {
                        fen=0;//???????
                        shi++;
                        if(shi==24)//????24?????
                        {
                                 shi=0;

                        }
                        write_sfm(4,shi);//24?????????????
                  }
                  write_sfm(7,fen);//??????????
            }
            write_sfm(10,miao);//?????????
   }

}

估計(jì)是中斷這一塊出了問(wèn)題，但是小白看不出來(lái)問(wèn)題，望指教。

1602時(shí)鐘源程序是這個(gè)
#include<reg51.h>
#define uchar unsigned char
#define uint unsigned int
sbit lcdrs=P1^5;  //??1602??RS?
sbit lcden=P1^6;//??1602??LCDEN?
sbit hw=P1^0;
uchar count,s1num,s4num;
char miao,shi,fen;
void delay(uint z)  //????
{
   uint x,y;
   for(x=z;x>0;x--)
            for(y=110;y>0;y--);
}

void write_com(uchar com)//???????
{
   lcdrs=0;
   lcden=0;
   P0=com;
   delay(5);
   lcden=1;
   delay(5);
   lcden=0;
}
void write_date(uchar date)//???????
{
   lcdrs=1;
   lcden=0;
   P0=date;
   delay(5);
   lcden=1;
   delay(5);
   lcden=0;
}
void write_alarm(uchar add1,uchar date1)//??????
{
   uchar shi,ge;
   shi=date1/10;//????2????????
   ge=date1%10;
   write_com(0x80+add1);//??????
   write_date(0x30+shi);//????????
   write_date(0x30+ge);//????????
}
void write_sfm(uchar add,uchar date)//??????
{
   uchar shi,ge;
   shi=date/10;//????2????????
   ge=date%10;
   write_com(0x80+0x40+add);//??????
   write_date(0x30+shi);//????????
   write_date(0x30+ge);//????????
}

void init()//?????
{
   lcden=0;
   shi=21;
   fen=59;
   miao=58;
   count=0;
   s1num=0;
   s4num=0;
   write_com(0x38);//???1602??
   write_com(0x0c);
   write_com(0x06);
   write_com(0x01);
   write_com(0x80);//????????


   delay(5);
   write_com(0x80+0x40+6);//???????????":"
   write_date(':');
   delay(5);
   write_com(0x80+0x40+9);
   write_date(':');
   delay(5);


                     write_sfm(10,miao);//????????
   write_sfm(7,fen);
   write_sfm(4,shi);

                     TMOD=0x01;//?????0????
   TH0=(65536-50000)/256;//??????
   TL0=(65536-50000)%256;
   EA=1;    //????
   ET0=1; //????0??
   TR0=1; //?????0
}

void main()//???
{
   init();//????????
   while(1)//????????
                     {
                              if(hw==0)
                              {
                                                delay(5);
                              write_com(0x80+3);
            write_date('*');
                                          delay(5);
            write_com(0x80+6);
            write_date(':');
                                          delay(5);
            write_com(0x80+9);
            write_date(':');
                                          delay(5);
                              write_com(0x80+12);
            write_date('*');
            delay(5);

                                    write_alarm(4,shi);//????????
            write_alarm(7,fen);
            write_alarm(10,miao);

                              }
                     }
}

void timer0() interrupt 1//???0??????
{
   TH0=(65536-50000)/256;//????????
   TL0=(65536-50000)%256;
   count++;       //??????
   if(count==17)//20?50???1?
   {
            count=0;
            miao++;
            if(miao==60)//???60?????
            {
                  miao=0;//??????
                  fen++;
                  if(fen==60)//????60?????
                  {
                        fen=0;//???????
                        shi++;
                        if(shi==24)//????24?????
                        {
                                 shi=0;

                        }
                        write_sfm(4,shi);//24?????????????
                  }
                  write_sfm(7,fen);//??????????
            }
            write_sfm(10,miao);//?????????
   }
}

按下按鈕可以顯示報(bào)警時(shí)間

望指教，十分感謝

5.png (78.69 KB, 下載次數(shù): 78)

整合之后的仿真圖，1602不亮

6.png (85.98 KB, 下載次數(shù): 86)

1602時(shí)鐘顯示仿真

7.png (10.34 KB, 下載次數(shù): 83)

1602顯示問(wèn)題

作者: xxpp2011 時(shí)間: 2020-4-12 17:37
先把keil里面的中文調(diào)好吧，configuration-editor-encoding-Chinese GB2312

作者: man1234567 時(shí)間: 2020-4-12 18:14
在時(shí)鐘程序里插入防盜模塊就可以了，調(diào)試要有耐心一步步地搞。

作者: xiashunxuan233 時(shí)間: 2020-4-12 21:02

xxpp2011 發(fā)表于 2020-4-12 17:37
先把keil里面的中文調(diào)好吧，configuration-editor-encoding-Chinese GB2312

好的

作者: xiashunxuan233 時(shí)間: 2020-4-12 21:05

man1234567 發(fā)表于 2020-4-12 18:14
在時(shí)鐘程序里插入防盜模塊就可以了，調(diào)試要有耐心一步步地搞。

謝謝您，但是能稍微具體一點(diǎn)點(diǎn)嗎，麻煩您了

歡迎光臨 (http://m.raoushi.com/bbs/)