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標(biāo)題: 關(guān)于單片機溫度傳感器程序的一些問題,如何觸發(fā)按鍵儲存溫度上下限 [打印本頁]

作者: kuailefeizai 時間: 2019-9-28 18:07
標(biāo)題: 關(guān)于單片機溫度傳感器程序的一些問題,如何觸發(fā)按鍵儲存溫度上下限
現(xiàn)在可以把數(shù)碼管檢測示數(shù)但不懂如何觸發(fā)報警和按鍵儲存溫度上下限，多天無解，還望解惑。
#include<reg52.h>
#include<intrins.h>
typedef  unsigned char uchar;
typedef  unsigned int uint;
#define MAIN_Fosc 11059200UL
sbit DS = P3^7;
sbit we1=P2^0;
sbit we2=P2^1;
sbit we3=P2^2;
sbit we4=P2^3;
sbit deep=P3^6;
sbit key=P3^5;
sbit key2=P3^4;
sbit key3=P3^3;
sbit key4=P3^2;
uchar temp;
uchar num;
uchar settemp=35;
uchar settemp2=10;
bit DS18B20;
uchar msec, sec;
unsigned char code leddata[]={

            0xC0,  //"0"
            0xF9,  //"1"
            0xA4,  //"2"
            0xB0,  //"3"
            0x99,  //"4"
            0x92,  //"5"
            0x82,  //"6"
            0xF8,  //"7"
            0x80,  //"8"
            0x90,  //"9"
            0x88,  //"A"
            0x83,  //"B"
            0xC6,  //"C"
            0xA1,  //"D"
            0x86,  //"E"
            0x8E,  //"F"
            0x89,  //"H"
            0xC7,  //"L"
            0xC8,  //"n"
            0xC1,  //"u"
            0x8C,  //"P"
            0xA3,  //"o"
            0xBF,  //"-"
            0xFF,  //???
            0xFF  //?????

                     };

void delay (uint z)
{
  uint x,y;
  for(x=z;x>0;x--)
  for(y=84;y>0;y--);
}
  void us(uchar us)//us???????
{
while(us--);
}
void display( uint value)
{
  we1=1;
  we1=0;
P0=0xff;
  P0=leddata[value/1000];
delay(1);
  we1=1;


  we2=0;
  P0&=0x7f;
  P0=leddata[value%1000/100];
  delay(1);
  we2=1;
we3=0;
  P0=0xff;
  P0=leddata[value%100/10];
  delay(1);
  we3=1;

  P0=0xff;
  P0=leddata[value%10];
  we4=0;
  delay(1);
  we4=1;

}
void display3( uint value)
{

  we1=1;
  we1=0;
P0=0xff;
  P0=leddata[value/1000];
delay(1);
  we1=1;


  we2=0;
  P0&=0x7f;
  P0=leddata[value%1000/100];
  delay(1);
  we2=1;
we3=0;
  P0=0xff;
  P0=leddata[value%100/10];
  delay(1);
  we3=1;

  P0=0xff;
  P0=leddata[value%10];
  we4=0;
  delay(1);
  we4=1;

}
void beep1()
{
temp=0xfe;
P1=temp;
delay(100);
while(1)
{
  temp=_crol_(temp,1);
  P1=temp;
  deep=~deep;
  delay(100);
}
}
void display2()
{

if(key == 0)
{
   delay(5);
if(key == 0)
{
while(!key);
settemp++;
delay(50);
if(settemp==99)
settemp=0;
delay(50);
}
}
if(key2 == 0)
{
   delay(5);
if(key2 == 0)
{
while(!key2);
if(settemp!=0)
settemp--;
delay(50);
}
}
if(key3 == 0)
{
   delay(5);
if(key3 == 0)
{
while(!key3);
settemp2++;
delay(50);
if(settemp2==99)
settemp2=0;
delay(50);
}
}
if(key4 == 0)
{
   delay(5);
if(key4 == 0)
{
while(!key4);
if(settemp2!=0)
settemp2--;
delay(50);
}
}

}

void duan ()
{

  EA=1;
  ET0=1;
  TR0=1;
  TMOD=0x01;
  TH0=0x4b;
  TL0=0xfd;

}
void  timer0() interrupt 1
{
  TH0=0x4b;
  TL0=0xfd;
  msec++;
  if(msec==20)
  {
msec=0;
  }
}

//?????????????
bit init()
{
bit i;
DS = 1;//??????
_nop_();
DS = 0;
us(75); //????????75*6.5+11.95=499.45us ????????????18B20???????????
DS=1;
us(4);//???
i = DS;
us(20); //141.95us ???????
DS = 1;
_nop_();
return (i);
}
void write (uchar dat)//д ???
{
uchar i;
for(i=0;i<8;i++)
{
  DS = 0;
  _nop_();//????д???
  DS = dat & 0x01;//?????????
  us(10);//76.95us
  DS = 1; //???????????????????д??
  _nop_();
  dat >>= 1;//??????
}
}
uchar read_byte()
{
uchar i, j, dat;
for(i=0;i<8;i++)
{
  DS = 0;
  _nop_();//?????????
  DS = 1;
  _nop_();//???????
  j = DS;
  us(10);//76.95us
  DS = 1;
  _nop_();
  dat = (j<<7)|(dat>>1);//????
}
return (dat);
}
void main()
{
  uint i;
  uchar L, M;
  init();//?????DS18B20
  write(0xcc);//???????ROM???
  write(0x4e);//????д????????
  write(0x18);
  write(0x10);
  write(0x7f);
  init();
  write(0xcc);
  write(0x48);
   while(1)
{
  init();//?????DS18B20
  write(0xcc);//???????ROM???
  write(0x44);//?????????????
      init();    //?????DS18B20
  write(0xcc);//???????ROM???
  write(0xbe);//???DS18B20??????
  L = read_byte();
  M = read_byte();
  i = M;
  i <<= 8;
  i |= L;
  i = i * 0.0625 * 100 + 0.05;
   display(i);
duan();
  if(key==0|key2==0|key3==0|key4==0)
  { if(key==0)
{
settemp=settemp*100;
while(!key);
while(1)
{
display3(settemp);}
   if(key2==0)
{ settemp=settemp*100;
while(!key2);
display3(settemp);}
   if(key3==0)
{ settemp2=settemp2*100;
while(!key3);
display3(settemp2);}
   if(key4==0)
{settemp2=settemp2*100;
while(!key4);
display3(settemp2);}
      }

}

原理圖QX-mini51.pdf

154.08 KB, 下載次數(shù): 20

原理圖

作者: level888 時間: 2020-2-23 18:57
發(fā)個源碼試試！

DS18b20 溫度檢測液晶顯示-溫度可調(diào)上下限1602顯示.zip

58.11 KB, 下載次數(shù): 19

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