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標題: 求一個51單片機矩陣加法方式,目前矩陣可以弄出來，但加減法不會 [打印本頁]

作者: 一個新手啊 時間: 2019-5-18 21:52
標題: 求一個51單片機矩陣加法方式,目前矩陣可以弄出來，但加減法不會
#include<reg51.h>
#define anjian P1
unsigned int keyshu;
unsigned int a;
unsigned int shumaguan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
void delay(unsigned int i)
{
while(i--);
}
void xianshi(unsigned int m)
{
unsigned int sw,gw;
sw=m/10;
gw=m%10;
P2=0X04;
P0=shumaguan[sw];
delay(1000);
P2=0X00;
P0=shumaguan[gw];
delay(1000);
}
void KEY()
{
P1=0X0F;
if(P1!=0x0f)
{
  delay(1000);
  if(P1!=0x0f)
  {
switch(anjian)
{
case(0x07): keyshu=0;break;
case(0x0b): keyshu=1;break;
case(0x0d): keyshu=2;break;
case(0x0e): keyshu=3;break;
}
P1=0XF0;
switch(anjian)
{
case(0x70): keyshu=keyshu;break;
case(0xB0): keyshu=keyshu+4;break;
case(0xD0): keyshu=keyshu+8;break;
case(0xE0): keyshu=keyshu+12;break;
}
while(a<50&&anjian!=0x0f)
{
delay(1000);
a++;
}
  }
}
}
void main()
{ while(1)
  {
  KEY();
  xianshi(keyshu);
  }
}#include<reg51.h>
#define anjian P1
unsigned int keyshu;
unsigned int a;
unsigned int shumaguan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
void delay(unsigned int i)
{
while(i--);
}
void xianshi(unsigned int m)
{
unsigned int sw,gw;
sw=m/10;
gw=m%10;
P2=0X04;
P0=shumaguan[sw];
delay(1000);
P2=0X00;
P0=shumaguan[gw];
delay(1000);
}
void KEY()
{
P1=0X0F;
if(P1!=0x0f)
{
  delay(1000);
  if(P1!=0x0f)
  {
switch(anjian)
{
case(0x07): keyshu=0;break;
case(0x0b): keyshu=1;break;
case(0x0d): keyshu=2;break;
case(0x0e): keyshu=3;break;
}
P1=0XF0;
switch(anjian)
{
case(0x70): keyshu=keyshu;break;
case(0xB0): keyshu=keyshu+4;break;
case(0xD0): keyshu=keyshu+8;break;
case(0xE0): keyshu=keyshu+12;break;
}
while(a<50&&anjian!=0x0f)
{
delay(1000);
a++;
}
  }
}
}
void main()
{ while(1)
  {
  KEY();
  xianshi(keyshu);
  }
}

作者: 一個新手啊 時間: 2019-5-18 21:53
矩陣可以弄出來，但加減法不會弄

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