標題: 28BYJ-48步進電機的每個檔位的轉速怎么測出來的?求大神告知 [打印本頁]
作者: ZDC948411285 時間: 2019-5-16 11:10
標題: 28BYJ-48步進電機的每個檔位的轉速怎么測出來的?求大神告知
步距角為5.625°，減速比為1/64.
//數(shù)碼管位 高位-----低位
//四個按鍵控制步進電機：正轉，反轉，加1，減1
//上電時電機啟動，數(shù)碼管上顯示速度最小檔1，加減檔位均能通過數(shù)碼管顯示出來，電機采用單雙八拍方式
//電機轉速一共10檔，通過按鍵調(diào)節(jié)轉速
//電機正轉時最高位數(shù)碼管顯示0，反轉時顯示1
#include<reg51.h>
#define uchar unsigned char
#define uint unsigned int
#define led P0//數(shù)碼管段選
//#define haha P2
sbit s1 = P3^4;sbit s2 = P3^5;sbit s3 = P3^6;sbit s4 =P3^7;//按鍵定義,s1正轉，s2反轉，s3加1，s4減1
sbit wei3 = P2^0;sbit wei2 = P2^2;sbit wei1 =P2^4;sbit wei0 = P2^6;//數(shù)碼管位選定義
sbit a = P1^7;sbit b = P1^6;sbit c = P1^5;sbit d =P1^4;//脈沖信號輸入端定義
uchar codetab[11]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,0xff};//共陽數(shù)碼管驅(qū)動信號0---9，不顯示
uchar code time_counter[10][2]={{0xda,0x1c},{0xde,0xe4},{0xe1,0xec},{0xe5,0xd4},{0xe9,0xbc}, //9.7 ----1ms
{0xed,0xa4},{0xf1,0x8c},{0xf5,0x74},{0xf9,0x5c},{0xfc,0x18}};
uchar codequdong[8]={0x80,0xc0,0x40,0x60,0x20,0x30,0x10,0x90};
uchar num1 = 0;//控制取勵磁信號變量
uchar num2 = 8;
uchar k=1;//加減檔位控制，1為最小檔
bit flag1 = 0;//初始正轉，正反轉標志
uchar buf[4]={0,10,0,1};//數(shù)碼管顯示緩存，正轉，不顯示，不顯示，顯示1檔位,高----低
//================================定時器0/1初始化函數(shù)================================
void T0_T1_init()
{
TMOD =0x11;//定時器0/1均工作于方式1,16位計時方式
TH1 = time_counter[k-1][0];
TL1 =time_counter[k-1][1];//定時器1，定時10ms用于步進電機轉速控制
TR1 = 1;
ET1= 1;//開定時器中斷
EA = 1;//開總中斷
}
//================================ms級延時函數(shù)=======================================
void delay1m(uint x)
{
uint i,j;
for(i=0;i<x;i++) //連數(shù)x次，約 x ms
for(j=0;j<120;j++); //數(shù)120 次，約1 ms
}
void display()
{
wei3=1;wei2=1;wei1=1;wei0=0;led= tab[buf[3]];delay1m(1);led=0xff;
wei3=1;wei2=1;wei1=0;wei0=1;led = tab[buf[2]];delay1m(1);led=0xff;
wei3=1;wei2=0;wei1=1;wei0=1;led = tab[buf[1]];delay1m(1);led=0xff;
wei3=0;wei2=1;wei1=1;wei0=1;led= tab[buf[0]];delay1m(1);led=0xff;
}
//================================主函數(shù)=============================================
void main()
{
T0_T1_init();
buf[1] =10;//不顯示
while(1)
{
display();
if(s1== 0)
{
delay1m(3);
if(s1== 0)
{
flag1= 0;//正轉
buf[0]= 0;//最高位顯示0
// haha = 0x00;//停止
}
while(!s1)display();
}
if(s2== 0 )
{
delay1m(3);
if(s2== 0)
{
flag1= 1;//反轉
buf[0]= 1;//最高位顯示1
// haha = 0x00;//停止
}
while(!s2)display();
}
if(s3== 0) //速度加1檔
{
delay1m(3);
if(s3== 0)
{
k++;
if(k> 10 )
{
k = 1;
}
buf[2]=k/10;
buf[3]=k%10;
}
while(!s3)display();
}
if(s4== 0) //速度減1檔
{
delay1m(3);
if(s4== 0)
{
k--;
if(k== 0)
{
k = 10;
}
buf[2]=k/10;
buf[3]=k%10;
}
while(!s4)display();
}
}
}
//==================================定時器1中斷函數(shù)，用于脈沖頻率控制=====================================
void time1_interrupt()interrupt 3
{
staticnum1 = 0;
staticnum2 = 0;
TH1 =time_counter[k-1][0];
TL1 =time_counter[k-1][1];//定時器1，定時1 用于步進電機轉速控制
if(flag1== 0)//正轉
{
switch(num1)
{
case0:a = 1;b = 0;c = 0;d = 0;break;
case1:a = 1;b = 1;c = 0;d = 0;break;
case2:a = 0;b = 1;c = 0;d = 0;break;
case3:a = 0;b = 1;c = 1;d = 0;break;
case4:a = 0;b = 0;c = 1;d = 0;break;
case5:a = 0;b = 0;c = 1;d = 1;break;
case6:a = 0;b = 0;c = 0;d = 1;break;
case7:a = 1;b = 0;c = 0;d = 1;break;
}
num1++;
if(num1== 8)num1 = 0;
}
else //反轉
{
switch(num2)
{
case0:a = 1;b = 0;c = 0;d = 1;break;
case1:a = 0;b = 0;c = 0;d = 1;break;
case2:a = 0;b = 0;c = 1;d = 1;break;
case3:a = 0;b = 0;c = 1;d = 0;break;
case4:a = 0;b = 1;c = 1;d = 0;break;
case5:a = 0;b = 1;c = 0;d = 0;break;
case6:a = 1;b = 1;c = 0;d = 0;break;
case7:a = 1;b = 0;c = 0;d = 0;break;
}
num2++;
if(num2== 8)num2 = 0;
}
}
作者: lfc315 時間: 2019-5-17 14:23
//定時器1，定時1 用于步進電機轉速控制
應該是通過設置K的值；
步進電機的速度是靠一步一步走出來的，走一步的時間變了，速度也就變了。
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