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標題: 單片機4*4*4光立方,一次以16LED燈為一組的亮滅程序如何修改? [打印本頁]

作者: abc357159 時間: 2019-1-8 17:39
標題: 單片機4*4*4光立方,一次以16LED燈為一組的亮滅程序如何修改?
因為我最終只找到了4個三極管，現在想改成如圖一次以16LED燈為一組的亮滅。跪求大佬幫忙改一下。我要3種以上亮滅方式要程序和仿真。以下是程序，也可以無視。

#include<reg51.h>#define uchar unsigned charunsigned char code smg[] = {0x50,0x61};void delay100ms(uchar data1ms){ uchar i,j,m; for(i=0;i<data1ms;i++) for(j=0;j<110;j++) for(m=0;m<100;m++);} void disp(uchar ceng,uchar lie1,uchar lie2 ) { delay100ms(5); P1=ceng; P2=lie1; P0=lie2; } void main(void) { unsigned char hang,shu1; unsigned char code C1[][16]={ {0x07,0x0B,0x0D,0x0E,0x0E,0x0C,0x08,0x00,0x00,0x08,0x0C,0x0E,0x0C,0x08,0x00,0x00}, {0x08,0x0C,0x0E,0x0C,0x08,0x00,0x00,0x08,0x0C,0x0E,0x0C,0x08,0x00,0x00,0x08,0x0C}, {0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E,0x0E}, {0x0C,0x08,0x00,0x00,0x08,0x0C,0x0E,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00}, {0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x0C,0x0E,0x0F,0x0E,0x0C,0x08,0x00}, {0x00,0x00,0x00,0x00,0x00,0x0D,0x0D,0x0D,0x05,0x09,0x09,0x09,0x0D,0x0D,0x0D,0x05}, {0x09,0x09,0x09,0x00,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09}, {0x09,0x09,0x09,0x09,0x09,0x09,0x09,0x09} }; unsigned char code L1[][16]={ {0xFF,0xFF,0xFF,0xFF,0x60,0x60,0x60,0x60,0x60,0x60,0x60,0x96,0x96,0x96,0x96,0x96}, {0x96,0x96,0x33,0x33,0x33,0x33,0x33,0x33,0x33,0xCC,0xCC,0xCC,0xCC,0xCC,0xCC,0xCC}, {0x01,0x03,0x07,0x0F,0x8E,0x8C,0x88,0x80,0x00,0x00,0x00,0x10,0x30,0x70,0x70,0x60}, {0x60,0x60,0x60,0x60,0x60,0x60,0x60,0xCC,0x0F,0x33,0x66,0xCC,0xF0,0x33,0x66,0xCC}, {0x66,0x33,0xF0,0xCC,0x66,0x33,0xF0,0xCC,0xCC,0xCC,0xCC,0xCC,0x60,0x60,0x60,0x60}, {0xE8,0x74,0x32,0x11,0x00,0x06,0x66,0x60,0x60,0x60,0x00,0x00,0x06,0x66,0x60,0x60}, {0x60,0x00,0x00,0x00,0x80,0x40,0x20,0x20,0x20,0x60,0x62,0x60,0x30,0x10,0x80,0xC0}, {0x60,0x60,0x60,0x60,0x64,0x60,0x30,0x10} // {0x01,0x02,0x04,0x08,0x80,0x40,0x20,0x10,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00},//¨￠D¨|?§?¨¨ }; unsigned char code L2[][16]={ {0xFF,0xFF,0xFF,0xFF,0x06,0x06,0x06,0x06,0x06,0x06,0x06,0x69,0x69,0x69,0x69,0x69}, {0x69,0x69,0xCC,0xCC,0xCC,0xCC,0xCC,0xCC,0xCC,0x33,0x33,0x33,0x33,0x33,0x33,0x33}, {0x00,0x00,0x00,0x00,0x00,0x08,0x88,0xC8,0xE8,0xF0,0x71,0x31,0x11,0x10,0x04,0x06}, {0x06,0x06,0x06,0x06,0x06,0x06,0x06,0x33,0xF0,0xCC,0x66,0x33,0x0F,0xCC,0x66,0x33}, {0x66,0xCC,0x0F,0x33,0x66,0xCC,0x0F,0x33,0x33,0x33,0x33,0x33,0x06,0x06,0x06,0x06}, {0x8E,0x47,0x23,0x11,0x00,0x00,0x00,0x06,0x06,0x06,0x66,0x60,0x00,0x00,0x06,0x06}, {0x06,0x66,0x60,0x00,0x08,0x0C,0x06,0x66,0x06,0x06,0x06,0x06,0x03,0x01,0x00,0x08}, {0x04,0x64,0x06,0x06,0x06,0x06,0x03,0x01} // {0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x02,0x04,0x08,0x80,0x40,0x20,0x10} }; while(1) { for(hang=0;hang<8;hang++) { for(shu1=0;shu1<16;shu1++) { disp(C1[hang][shu1],L1[hang][shu1],L2[hang][shu1]); } } } }
#ifndef __REG51_H__#define __REG51_H__/* BYTE Register */sfr P0 = 0x80;sfr P1 = 0x90;sfr P2 = 0xA0;sfr P3 = 0xB0;sfr PSW = 0xD0;sfr ACC = 0xE0;sfr B = 0xF0;sfr SP = 0x81;sfr DPL = 0x82;sfr DPH = 0x83;sfr PCON = 0x87;sfr TCON = 0x88;sfr TMOD = 0x89;sfr TL0 = 0x8A;sfr TL1 = 0x8B;sfr TH0 = 0x8C;sfr TH1 = 0x8D;sfr IE = 0xA8;sfr IP = 0xB8;sfr SCON = 0x98;sfr SBUF = 0x99;/* BIT Register *//* PSW */sbit CY = 0xD7;sbit AC = 0xD6;sbit F0 = 0xD5;sbit RS1 = 0xD4;sbit RS0 = 0xD3;sbit OV = 0xD2;sbit P = 0xD0;/* TCON */sbit TF1 = 0x8F;sbit TR1 = 0x8E;sbit TF0 = 0x8D;sbit TR0 = 0x8C;sbit IE1 = 0x8B;sbit IT1 = 0x8A;sbit IE0 = 0x89;sbit IT0 = 0x88;///* IE */sbit EA = 0xAF;sbit ES = 0xAC;sbit ET1 = 0xAB;sbit EX1 = 0xAA;sbit ET0 = 0xA9;sbit EX0 = 0xA8;/* IP */ sbit PS = 0xBC;sbit PT1 = 0xBB;sbit PX1 = 0xBA;sbit PT0 = 0xB9;sbit PX0 = 0xB8;/* P3 */sbit RD = 0xB7;sbit WR = 0xB6;sbit T1 = 0xB5;sbit T0 = 0xB4;sbit INT1 = 0xB3;sbit INT0 = 0xB2;sbit TXD = 0xB1;sbit RXD = 0xB0;/* SCON */sbit SM0 = 0x9F;sbit SM1 = 0x9E;sbit SM2 = 0x9D;sbit REN = 0x9C;sbit TB8 = 0x9B;sbit RB8 = 0x9A;sbit TI = 0x99;sbit RI = 0x98;#endif

作者: yzwzfyz 時間: 2019-1-9 08:55
如果你有“光立方”的概念就麻煩了，先拋棄所謂的“光立方”！
它就是64個LED燈，你用掃描顯示的方式顯示它們。
建立一個16*8字節的顯示緩沖區，區內的每一個位對應一個燈的明暗！
寫一段掃描顯示程序，將顯示緩沖區的數據，送到各自的LED顯示。
接下來就方便了：想讓哪個燈暗/亮，只要修改顯示緩沖區中的對應位的0/1就可以了。

作者: weidoit 時間: 2019-1-9 09:14
4個三極管由4個IO控制，16個IO送顯示的內容，動態掃描就可以了。

歡迎光臨 (http://m.raoushi.com/bbs/)